Sentence


Parse

Que
S[wq]/(S[dcl]\NP)
 
é
((S[dcl]\NP)/PP)/NP
 
que
PP/NP
 
está
N/(S[to]\NP)
 
a
(S[to]\NP)/(S[b]\NP)
 
ler
S[b]\NP
 
S[to]\NP
> 0
N
> 0
NP
*
,
NP\NP
 
NP
< 0
PP
> 0
(S[dcl]\NP)\((S[dcl]\NP)/PP)
T <
(S[dcl]\NP)/NP
< 1×
senhora
N
 
NP
*
S[dcl]\NP
> 0
S[wq]
> 0
?
S[wq]\S[wq]
 
S[wq]
< 0

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