Sentence


Parse

Se
(S[dcl]/S[dcl])/S[dcl]
 
eu
N
 
NP
*
NP/(NP\NP)
T >
soubesse
S[dcl]\NP
 
S[dcl]/(NP\NP)
< 1×
o
(NP\NP)/NP
 
endereço
N/N
 
dela
N
 
N
> 0
NP
*
,
NP\NP
 
NP
< 0
NP\NP
> 0
S[dcl]
> 0
S[dcl]/S[dcl]
> 0
escreveria
N/N
 
para
N
 
N
> 0
NP
*
ela
S[dcl]\NP
 
S[dcl]
< 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0
S[dcl]
> 0

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