Sentence


Parse

Tom
N
 
NP
*
não
(S[dcl]\NP)/(S[ng]\NP)
 
acorda
S[pss]\NP
 
S[dcl]/S[dcl]
*
cedo
S[ng]\NP
 
(S[dcl]\NP)\((S[dcl]\NP)/(S[ng]\NP))
T <
(S[dcl]\NP)\((S[dcl]\NP)/(S[ng]\NP))
> n
S[dcl]\NP
< 0
S[dcl]
< 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0

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