Sentence


Parse

Uma
N
 
nova
N\N
 
N
< 0
NP
*
dificuldade
(S[dcl]\NP)/NP
 
apresentou
N/N
 
-
N
 
N
> 0
NP
*
S[dcl]\NP
> 0
se
(S[dcl]\NP)\(S[dcl]\NP)
 
S[dcl]\NP
< 0
S[dcl]
< 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0

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