Sentence


Parse

Vale
S[dcl]/PP
 
a
PP/NP
 
pena
NP
 
PP
> 0
S[dcl]
> 0
tentar
S[ng]\NP
 
S[dcl]/S[dcl]
*
.
S[dcl]\S[dcl]
 
S[dcl]\S[dcl]
> 1×
S[dcl]
< 0

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