Sentence


Parse

¡
S[dcl]/PP
 
A
PP/NP
 
buen
N
 
entendedor
NP
 
S[dcl]/(S[dcl]\NP)
T >
pocas
(S[dcl]\NP)/NP
 
palabras
((S[dcl]\NP)\(S[dcl]\NP))/NP
 
bastan
N
 
NP
*
(S[dcl]\NP)\(S[dcl]\NP)
> 0
(S[dcl]\NP)/NP
< 1×
S[dcl]/NP
> 1
N\N
*
N
< 0
NP
*
PP
> 0
S[dcl]
> 0
!
S[dcl]\S[dcl]
 
S[dcl]
< 0

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