Sentence


Parse

Debemos
NP/NP
 
encontrar
(S[dcl]\NP)/NP
 
una
NP/N
 
gasolinera
N
 
NP
> 0
NP\(NP/NP)
T <
(S[dcl]\NP)\(NP/NP)
> 1×
S[dcl]\NP
< 0
porque
N
 
NP
*
S[dcl]/(S[dcl]\NP)
T >
dentro
N/N
 
de
N
 
N
> 0
NP
*
poco
N/N
 
este
N/N
 
auto
N
 
N
> 0
N
> 0
NP
*
se
((S[dcl]\NP)\(S[dcl]\NP))/S[dcl]
 
quedará
S[dcl]\NP
 
(S[dcl]\NP)/((S[dcl]\NP)\(S[dcl]\NP))
T >
sin
((S[dcl]\NP)\(S[dcl]\NP))/S[dcl]
 
bencina
S[dcl]\NP
 
((S[dcl]\NP)\(S[dcl]\NP))\NP
> 1×
(S[dcl]\NP)\NP
> 1×
(((S[dcl]\NP)\(S[dcl]\NP))\NP)\NP
> n
((S[dcl]\NP)\(S[dcl]\NP))\NP
< 0
(S[dcl]\NP)\(S[dcl]\NP)
< 0
S[dcl]\(S[dcl]\NP)
> 1×
S[dcl]
< 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0

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