Sentence


Parse

Esto
S[dcl]/NP
 
es
N
 
suficiente
N/N
 
para
N/N
 
S[adj]\NP
 
N\N
*
N\N
> 1×
N\N
> 1×
N
< 0
NP
*
S[dcl]
> 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0

Use with der.css.

Use with ccgsym.sty and tikzlibraryccgder.code.tex.