Sentence


Parse

Has
N
 
NP
*
vuelto
S[dcl]\NP
 
S[dcl]
< 0
a
(S[to]\NP)/(S[b]\NP)
 
cometer
(S[b]\NP)/NP
 
exactamente
N
 
el
(N\N)/N
 
mismo
N/N
 
error
N
 
N
> 0
N\N
> 0
N
< 0
NP
*
S[b]\NP
> 0
S[to]\NP
> 0
S[dcl]/S[dcl]
*
.
S[dcl]\S[dcl]
 
S[dcl]\S[dcl]
> 1×
S[dcl]
< 0

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