Sentence


Parse

Invita
S[dcl]/PP
 
a
PP/NP
 
Mary
N
 
NP
*
PP
> 0
S[dcl]
> 0
a
(S[to]\NP)/(S[b]\NP)
 
cenar
S[b]\NP
 
S[to]\NP
> 0
S[dcl]/S[dcl]
*
.
S[dcl]\S[dcl]
 
S[dcl]\S[dcl]
> 1×
S[dcl]
< 0

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