CCGWeb - Tienes que responder a estas preguntas.

Tienes

NP/N

que

(S[dcl]\NP)/(S[dcl]\NP)

responder

S[dcl]\NP

> ⁰

((S[dcl]\NP)\(S[dcl]\NP))/NP

estas

(S[dcl]\NP)\(S[dcl]\NP)

> ⁰

S[dcl]\NP

< ⁰

S[dcl]/N

< ¹_×

preguntas

S[dcl]

> ⁰

S[dcl]\S[dcl]

S[dcl]

< ⁰

 <div class="der">
<table class="constituent binaryrule" data-cat="S[dcl]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="S[dcl]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="S[dcl]/N">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="Tienes" data-from="0" data-to="6" data-cat="NP/N">
<tr><td class="token">Tienes</td></tr>
<tr><td class="cat" tabindex="0">NP/N</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="S[dcl]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="que" data-from="7" data-to="10" data-cat="(S[dcl]\NP)/(S[dcl]\NP)">
<tr><td class="token">que</td></tr>
<tr><td class="cat" tabindex="0">(S[dcl]\NP)/(S[dcl]\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="responder" data-from="11" data-to="20" data-cat="S[dcl]\NP">
<tr><td class="token">responder</td></tr>
<tr><td class="cat" tabindex="0">S[dcl]\NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]\NP</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="(S[dcl]\NP)\(S[dcl]\NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="a" data-from="21" data-to="22" data-cat="((S[dcl]\NP)\(S[dcl]\NP))/NP">
<tr><td class="token">a</td></tr>
<tr><td class="cat" tabindex="0">((S[dcl]\NP)\(S[dcl]\NP))/NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent unaryrule" data-cat="NP">
<tr class="daughters"><td class="daughter daughter-only"><table class="constituent lex" data-token="estas" data-from="23" data-to="28" data-cat="N">
<tr><td class="token">estas</td></tr>
<tr><td class="cat" tabindex="0">N</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td></tr>
<tr><td class="rulecat"><div class="rulecat">
<div class="cat">NP</div>
<div class="rule" title="Type Changing">
									*
								</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S[dcl]\NP)\(S[dcl]\NP)</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]\NP</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]/N</div>
<div class="rule" title="Backward Crossed Composition">&lt; <sup>1</sup><sub>×</sub>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="preguntas" data-from="29" data-to="38" data-cat="N">
<tr><td class="token">preguntas</td></tr>
<tr><td class="cat" tabindex="0">N</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="." data-from="38" data-to="39" data-cat="S[dcl]\S[dcl]">
<tr><td class="token">.</td></tr>
<tr><td class="cat" tabindex="0">S[dcl]\S[dcl]</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table> </div>

Use with der.css.

\begin{tikzpicture}[ampersand replacement=\&]
	\matrix [column sep=9pt] at (0, 0) {
		\lexnode*{idm20}{Tienes}{\catNP/\catN}{} \&
		\lexnode*{idm44}{que}{(\catS[dcl]\?\catNP)/(\catS[dcl]\?\catNP)}{} \&
		\lexnode*{idm58}{responder}{\catS[dcl]\?\catNP}{} \&
		\lexnode*{idm79}{a}{((\catS[dcl]\?\catNP)\?(\catS[dcl]\?\catNP))/\catNP}{} \&
		\lexnode*{idm98}{estas}{\catN}{} \&
		\lexnode*{idm106}{preguntas}{\catN}{} \&
		\lexnode*{idm114}{.}{\catS[dcl]\?\catS[dcl]}{} \\
	};
	\binnode*{idm37}{idm44-cat}{idm58-cat}{\FC{0}}{\catS[dcl]\?\catNP}{}
	\unnode*{idm95}{idm98-cat}{*}{\catNP}{}
	\binnode*{idm68}{idm79-cat}{idm95}{\FC{0}}{(\catS[dcl]\?\catNP)\?(\catS[dcl]\?\catNP)}{}
	\binnode*{idm30}{idm37}{idm68}{\BC{0}}{\catS[dcl]\?\catNP}{}
	\binnode*{idm13}{idm20-cat}{idm30}{\BXC{1}}{\catS[dcl]/\catN}{}
	\binnode*{idm8}{idm13}{idm106-cat}{\FC{0}}{\catS[dcl]}{}
	\binnode*{idm3}{idm8}{idm114-cat}{\BC{0}}{\catS[dcl]}{}
\end{tikzpicture}

Use with ccgsym.sty and tikzlibraryccgder.code.tex.

Sentence

Parse

Translations