Sentence


Parse

Todos
NP/N
 
quieren
S[dcl]/PP
 
a
PP/NP
 
Tom
N
 
NP\(NP/N)
T <
PP\(NP/N)
> 1×
S[dcl]\(NP/N)
> 1×
S[dcl]
< 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0

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