CCGWeb - Tu nombre me es familiar.

nombre

(S[b]\NP)/NP

((S[dcl]\NP)/(S[b]\NP))\NP

(S[dcl]\NP)/(S[b]\NP)

< ⁰

familiar

(S[b]\NP)\((S[b]\NP)/NP)

T ^<

(S[dcl]\NP)\((S[b]\NP)/NP)

> ¹_×

S[dcl]\NP

< ⁰

S[dcl]

< ⁰

S[dcl]\S[dcl]

S[dcl]

< ⁰

 <div class="der">
<table class="constituent binaryrule" data-cat="S[dcl]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="S[dcl]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="Tu" data-from="0" data-to="2" data-cat="NP">
<tr><td class="token">Tu</td></tr>
<tr><td class="cat" tabindex="0">NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="nombre" data-from="3" data-to="9" data-cat="(S[b]\NP)/NP">
<tr><td class="token">nombre</td></tr>
<tr><td class="cat" tabindex="0">(S[b]\NP)/NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="(S[dcl]\NP)\((S[b]\NP)/NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="(S[dcl]\NP)/(S[b]\NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="me" data-from="10" data-to="12" data-cat="NP">
<tr><td class="token">me</td></tr>
<tr><td class="cat" tabindex="0">NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="es" data-from="13" data-to="15" data-cat="((S[dcl]\NP)/(S[b]\NP))\NP">
<tr><td class="token">es</td></tr>
<tr><td class="cat" tabindex="0">((S[dcl]\NP)/(S[b]\NP))\NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S[dcl]\NP)/(S[b]\NP)</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent unaryrule" data-cat="(S[b]\NP)\((S[b]\NP)/NP)">
<tr class="daughters"><td class="daughter daughter-only"><table class="constituent unaryrule" data-cat="NP">
<tr class="daughters"><td class="daughter daughter-only"><table class="constituent lex" data-token="familiar" data-from="16" data-to="24" data-cat="N">
<tr><td class="token">familiar</td></tr>
<tr><td class="cat" tabindex="0">N</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td></tr>
<tr><td class="rulecat"><div class="rulecat">
<div class="cat">NP</div>
<div class="rule" title="Type Changing">
									*
								</div>
</div></td></tr>
</table></td></tr>
<tr><td class="rulecat"><div class="rulecat">
<div class="cat">(S[b]\NP)\((S[b]\NP)/NP)</div>
<div class="rule" title="Backward Type Raising">
									T <sup>&lt;</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S[dcl]\NP)\((S[b]\NP)/NP)</div>
<div class="rule" title="Forward Crossed Composition">&gt; <sup>1</sup><sub>×</sub>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]\NP</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="." data-from="24" data-to="25" data-cat="S[dcl]\S[dcl]">
<tr><td class="token">.</td></tr>
<tr><td class="cat" tabindex="0">S[dcl]\S[dcl]</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table> </div>

Use with der.css.

\begin{tikzpicture}[ampersand replacement=\&]
	\matrix [column sep=9pt] at (0, 0) {
		\lexnode*{idm13}{Tu}{\catNP}{} \&
		\lexnode*{idm28}{nombre}{(\catS[b]\?\catNP)/\catNP}{} \&
		\lexnode*{idm64}{me}{\catNP}{} \&
		\lexnode*{idm72}{es}{((\catS[dcl]\?\catNP)/(\catS[b]\?\catNP))\?\catNP}{} \&
		\lexnode*{idm102}{familiar}{\catN}{} \&
		\lexnode*{idm110}{.}{\catS[dcl]\?\catS[dcl]}{} \\
	};
	\binnode*{idm53}{idm64-cat}{idm72-cat}{\BC{0}}{(\catS[dcl]\?\catNP)/(\catS[b]\?\catNP)}{}
	\unnode*{idm99}{idm102-cat}{*}{\catNP}{}
	\unnode*{idm88}{idm99}{*}{(\catS[b]\?\catNP)\?((\catS[b]\?\catNP)/\catNP)}{}
	\binnode*{idm40}{idm53}{idm88}{\FXC{1}}{(\catS[dcl]\?\catNP)\?((\catS[b]\?\catNP)/\catNP)}{}
	\binnode*{idm21}{idm28-cat}{idm40}{\BC{0}}{\catS[dcl]\?\catNP}{}
	\binnode*{idm8}{idm13-cat}{idm21}{\BC{0}}{\catS[dcl]}{}
	\binnode*{idm3}{idm8}{idm110-cat}{\BC{0}}{\catS[dcl]}{}
\end{tikzpicture}

Use with ccgsym.sty and tikzlibraryccgder.code.tex.

Sentence

Parse

Translations